1. Assignment for team 1: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 205N_ID^(2))mod1023 0<=n<1023 where x(i+10) = (x(i+3) + x(i))mod2 and [x(9) x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [1 0 0 0 0 1 0 1 0 1] -------------------------------------------------- |2. Assignment for team 2: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 1366N_ID^(2))mod8191 0<=n<8191 where x(i+13) = (x(i+12) + x(i+10) + x(i+9) + x(i))mod2 and [x(12) x(11) x(10) x(9) x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [1 1 1 0 0 1 0 1 0 0 0 1 0] -------------------------------------------------- |3. Assignment for team 3: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 683N_ID^(2))mod4095 0<=n<4095 where x(i+12) = (x(i+11) + x(i+8) + x(i+6) + x(i))mod2 and [x(11) x(10) x(9) x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [0 0 1 0 0 1 0 0 0 0 0 1] -------------------------------------------------- |4. Assignment for team 4: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 683N_ID^(2))mod4095 0<=n<4095 where x(i+12) = (x(i+11) + x(i+8) + x(i+6) + x(i))mod2 and [x(11) x(10) x(9) x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [1 0 0 1 0 1 0 1 0 1 0 1] -------------------------------------------------- |5. Assignment for team 5: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 1366N_ID^(2))mod8191 0<=n<8191 where x(i+13) = (x(i+12) + x(i+10) + x(i+9) + x(i))mod2 and [x(12) x(11) x(10) x(9) x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [0 0 0 0 0 0 1 1 0 1 0 0 0] -------------------------------------------------- |6. Assignment for team 6: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 205N_ID^(2))mod1023 0<=n<1023 where x(i+10) = (x(i+3) + x(i))mod2 and [x(9) x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [0 0 0 0 1 0 1 0 0 0] -------------------------------------------------- |7. Assignment for team 7: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 1366N_ID^(2))mod8191 0<=n<8191 where x(i+13) = (x(i+12) + x(i+10) + x(i+9) + x(i))mod2 and [x(12) x(11) x(10) x(9) x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [0 1 0 0 0 0 0 1 1 1 0 1 1] -------------------------------------------------- |8. Assignment for team 8: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 205N_ID^(2))mod1023 0<=n<1023 where x(i+10) = (x(i+3) + x(i))mod2 and [x(9) x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [1 1 0 1 1 1 1 0 1 0] -------------------------------------------------- |9. Assignment for team 9: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 128N_ID^(2))mod511 0<=n<511 where x(i+9) = (x(i+4) + x(i))mod2 and [x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [1 0 0 0 1 0 1 0 1] -------------------------------------------------- |10. Assignment for team 10: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 205N_ID^(2))mod1023 0<=n<1023 where x(i+10) = (x(i+3) + x(i))mod2 and [x(9) x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [1 0 0 1 1 1 1 0 1 0] -------------------------------------------------- |11. Assignment for team 11: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 64N_ID^(2))mod255 0<=n<255 where x(i+8) = (x(i+4) + x(i+3) + x(i+2) + x(i))mod2 and [x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [0 0 0 1 0 0 0 1] -------------------------------------------------- |12. Assignment for team 12: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 410N_ID^(2))mod2047 0<=n<2047 where x(i+11) = (x(i+2) + x(i))mod2 and [x(10) x(9) x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [0 1 0 0 1 1 0 1 0 0 0] -------------------------------------------------- |13. Assignment for team 13: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 205N_ID^(2))mod1023 0<=n<1023 where x(i+10) = (x(i+3) + x(i))mod2 and [x(9) x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [0 0 0 1 0 1 0 0 1 0] -------------------------------------------------- |14. Assignment for team 14: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 64N_ID^(2))mod255 0<=n<255 where x(i+8) = (x(i+4) + x(i+3) + x(i+2) + x(i))mod2 and [x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [0 0 0 1 0 1 0 0] -------------------------------------------------- |15. Assignment for team 15: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 64N_ID^(2))mod255 0<=n<255 where x(i+8) = (x(i+4) + x(i+3) + x(i+2) + x(i))mod2 and [x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [0 1 1 1 1 0 1 0] -------------------------------------------------- |16. Assignment for team 16: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 683N_ID^(2))mod4095 0<=n<4095 where x(i+12) = (x(i+11) + x(i+8) + x(i+6) + x(i))mod2 and [x(11) x(10) x(9) x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [1 1 1 1 1 1 1 1 1 0 0 1] -------------------------------------------------- |17. Assignment for team 17: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 128N_ID^(2))mod511 0<=n<511 where x(i+9) = (x(i+4) + x(i))mod2 and [x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [1 1 1 0 1 1 0 0 1] -------------------------------------------------- |18. Assignment for team 18: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 64N_ID^(2))mod255 0<=n<255 where x(i+8) = (x(i+4) + x(i+3) + x(i+2) + x(i))mod2 and [x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [1 0 0 1 0 1 1 0] -------------------------------------------------- |19. Assignment for team 19: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 205N_ID^(2))mod1023 0<=n<1023 where x(i+10) = (x(i+3) + x(i))mod2 and [x(9) x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [0 0 0 1 1 1 1 1 0 1] -------------------------------------------------- |20. Assignment for team 20: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 683N_ID^(2))mod4095 0<=n<4095 where x(i+12) = (x(i+11) + x(i+8) + x(i+6) + x(i))mod2 and [x(11) x(10) x(9) x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [0 0 1 0 0 0 1 0 0 0 1 1] -------------------------------------------------- |21. Assignment for team 21: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 205N_ID^(2))mod1023 0<=n<1023 where x(i+10) = (x(i+3) + x(i))mod2 and [x(9) x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [0 1 0 1 0 0 0 0 1 0] -------------------------------------------------- |22. Assignment for team 22: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 64N_ID^(2))mod255 0<=n<255 where x(i+8) = (x(i+4) + x(i+3) + x(i+2) + x(i))mod2 and [x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [0 0 1 0 0 1 0 1] -------------------------------------------------- |23. Assignment for team 23: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 1366N_ID^(2))mod8191 0<=n<8191 where x(i+13) = (x(i+12) + x(i+10) + x(i+9) + x(i))mod2 and [x(12) x(11) x(10) x(9) x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [1 0 1 0 0 0 0 0 0 0 1 1 0] -------------------------------------------------- |24. Assignment for team 24: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 205N_ID^(2))mod1023 0<=n<1023 where x(i+10) = (x(i+3) + x(i))mod2 and [x(9) x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [1 0 1 0 0 0 0 0 0 1] -------------------------------------------------- |25. Assignment for team 25: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 128N_ID^(2))mod511 0<=n<511 where x(i+9) = (x(i+4) + x(i))mod2 and [x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [0 1 0 1 0 0 1 1 0] -------------------------------------------------- |26. Assignment for team 26: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 64N_ID^(2))mod255 0<=n<255 where x(i+8) = (x(i+4) + x(i+3) + x(i+2) + x(i))mod2 and [x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [1 0 0 0 0 1 1 0] -------------------------------------------------- |27. Assignment for team 27: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 64N_ID^(2))mod255 0<=n<255 where x(i+8) = (x(i+4) + x(i+3) + x(i+2) + x(i))mod2 and [x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [0 0 1 1 0 1 1 1] -------------------------------------------------- |28. Assignment for team 28: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 1366N_ID^(2))mod8191 0<=n<8191 where x(i+13) = (x(i+12) + x(i+10) + x(i+9) + x(i))mod2 and [x(12) x(11) x(10) x(9) x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [1 1 0 0 0 1 0 0 0 1 1 0 0] -------------------------------------------------- |29. Assignment for team 29: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 683N_ID^(2))mod4095 0<=n<4095 where x(i+12) = (x(i+11) + x(i+8) + x(i+6) + x(i))mod2 and [x(11) x(10) x(9) x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [0 0 1 0 0 0 0 1 0 0 0 1] -------------------------------------------------- |30. Assignment for team 30: The sequence d_PSS(n) for the primary synchronization signal is defined by d_PSS(n) = 1 - 2x(m) m = (n + 128N_ID^(2))mod511 0<=n<511 where x(i+9) = (x(i+4) + x(i))mod2 and [x(8) x(7) x(6) x(5) x(4) x(3) x(2) x(1) x(0)] = [0 1 0 0 1 0 1 1 0] --------------------------------------------------